A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
\[{{({{F}_{C}})}_{heavier}}={{({{F}_{C}})}_{lighter}}\] \[\Rightarrow \] \[\frac{2m{{V}^{2}}}{(r/2)}=\frac{m{{(nV)}^{2}}}{r}\Rightarrow {{n}^{2}}=4\Rightarrow n=2\]You need to login to perform this action.
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