A) 2 sin A
B) 2 cos A
C) \[\frac{\cos A}{2}\]
D) tan A
Correct Answer: B
Solution :
Apply snells law at PQ \[{{\mu }_{1}}\,\,\sin 2\operatorname{A}\,\,cosA={{\mu }_{2}}\sin \operatorname{A}\] \[{{\mu }_{1}}2\,\,\sin \operatorname{A}\,\,cosA={{\mu }_{2}}\sin \operatorname{A}\] \[1\times 2\,\,\cos A={{\mu }_{2}}\] \[{{\mu }_{2}}=2\cos \operatorname{A}\]You need to login to perform this action.
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