A) 50V
B) 70V
C) 130V
D) 10V
Correct Answer: A
Solution :
\[{{\operatorname{V}}_{z}}=\sqrt{{{V}^{2}}_{R}+{{\left( {{V}_{L}}-{{V}_{C}} \right)}^{2}}}\] \[{{\operatorname{V}}_{z}}=\sqrt{{{\left( 40 \right)}^{2}}+{{\left( 60-30 \right)}^{2}}}\] \[{{\operatorname{V}}_{z}}=\sqrt{1600+900}\] \[{{\operatorname{V}}_{z}}=50\operatorname{V}\]You need to login to perform this action.
You will be redirected in
3 sec