A) Acetic acid
B) Glucose
C) Molecular hydrogen
D) Fructose
Correct Answer: B
Solution :
Because glucose has free - CHO group. Hence, it has reducing power, and it is a reducing sugar. It can reduce silver nitrate to form silver (tollen's reagent). We can write the reaction as follow's. \[2AgN{{O}_{3}} + R-CHO+2NaOH=2Ag+R-\] \[\operatorname{COOH}+ 2NaN{{0}_{3}}+{{H}_{2}}0\] Where R - CHO is glucose.You need to login to perform this action.
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