A) \[{{\operatorname{CH}}_{2}}=CHCH=CHC{{H}_{3}}\]
B) \[C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{2}}C=CH\]
C) \[{{\left( C{{H}_{3}} \right)}_{2}}CH-C=C{{H}_{2}}\]
D) \[{{\left( C{{H}_{2}} \right)}_{2}}CH-C=CH\]
Correct Answer: D
Solution :
As terminal alkyne containing \[{{\left( C{{H}_{3}} \right)}_{2}}CH\] group when this compound goes on oxidation with \[{{\operatorname{KMnO}}_{4}},\]it will give carboxylic acid. \[\]You need to login to perform this action.
You will be redirected in
3 sec