A) \[{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}={{\left[ {{N}_{2}}{{O}_{5}} \right]}_{0}}+kt\]
B) \[\left[ {{N}_{2}}{{O}_{5}} \right]o={{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}{{e}^{kt}}\]
C) \[log{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}=log{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}+kt\]
D) \[In\,\,\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{t}}}=kt\]
Correct Answer: D
Solution :
\[\operatorname{In}=\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{T}}}=kt\] \[\operatorname{k}=\frac{1}{t}In\frac{a}{a-x}\] \[=\frac{1}{t}In\frac{{{C}_{o}}}{{{C}_{t}}}\] \[=\frac{1}{t}\operatorname{In}\frac{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{o}}}{{{\left[ {{N}_{2}}{{O}_{5}} \right]}_{T}}}\] k is the rate constant.You need to login to perform this action.
You will be redirected in
3 sec