A) \[n=\frac{2h{{v}_{o}}}{g{{w}^{2}}}\]
B) \[n=\frac{2h{{v}^{2}}_{o}}{gw}\]
C) \[n=\frac{h{{v}^{2}}_{o}}{g{{w}^{2}}}\]
D) \[n=\frac{2h{{v}^{2}}_{o}}{g{{w}^{2}}}\]
Correct Answer: D
Solution :
\[y=nh=ut+\frac{1}{2}g{{t}^{2}}\] Since ball is released u=0 \[y=nh=\frac{1}{2}g{{t}^{2}}\] (1) \[x=Range=nw={{(velocity)}_{Horizonrtal}}\times time\,\,of\] \[flight\] \[x=nw={{v}_{o}}\times t\] \[t=\frac{nw}{{{v}_{o}}}\] (2) \[By\,\,\,\left( 1 \right)\,\,\And \,\,\left( 2 \right)\,\,n=\frac{2h{{v}^{2}}_{0}}{g{{w}^{2}}}\]You need to login to perform this action.
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