A) pV
B) 2pV
C) 3pV
D) 6Pv
Correct Answer: C
Solution :
work done by the gas = area under P-V graph \[\operatorname{W}=\frac{1}{2}AB\times ACW=\frac{1}{2}\times 3P\times 2V\] \[\operatorname{W}=3PV\]You need to login to perform this action.
You will be redirected in
3 sec