A) Zero
B) \[2{{P}_{0}}{{V}_{0}}\]
C) \[{{P}_{0}}V\]
D) \[\frac{3}{2}{{P}_{0}}{{V}_{0}}\]
Correct Answer: A
Solution :
\[{{\operatorname{W}}_{AEDA}}\,=+Area\,\,of\,\,\Delta \operatorname{AED}\] \[=\frac{1}{2}\times {{P}_{o}}{{V}_{o}}W=+ve\,\left( clockwise \right)\] \[{{\operatorname{W}}_{\operatorname{BCEB}}}\,=+Area\,\,of\,\,\Delta \operatorname{BCE}\] \[=-\frac{1}{2}\times {{P}_{o}}{{V}_{o}}W=-ve\,\left( Anticlockwise \right)\]\[{{W}_{net}}={{\operatorname{W}}_{AEDA}}+{{\operatorname{W}}_{\operatorname{BCEB}}}\] \[{{W}_{net}}=0\]You need to login to perform this action.
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