A) -900J
B) -900KJ
C) 270J
D) 900KJ
Correct Answer: B
Solution :
\[\operatorname{W}=-P\Delta V\] \[\Delta \operatorname{V}={{V}_{2}}-{{V}_{1}}\] \[=1\times {{10}^{-2}}{{\operatorname{m}}^{3}}-\left( 1\times {{10}^{-3}}{{\operatorname{m}}^{2}} \right)\] \[\operatorname{P}=1\times 1{{0}^{5}}N{{m}^{-2}}\] \[W=-1{{0}^{5}}N{{m}^{-2}}\left( {{10}^{-2}}-{{10}^{-3}} \right){{\operatorname{m}}^{3}}\] \[=-1{{0}^{5}}\times {{10}^{-3}}\left( 10-1 \right)\] \[=-1{{0}^{2}}\left( 9 \right)\] \[=-900N\,m/J or\,\,-900KJ\]You need to login to perform this action.
You will be redirected in
3 sec