A) 24 min
B) 8min
C) 16 min
D) 4min
Correct Answer: C
Solution :
For the 1st order reaction \[\operatorname{k}=\frac{2.303}{t}\,\,\,log\frac{a}{a-x}\] \[\operatorname{when}\,\,=\frac{75a}{100}=0.75a\] \[\operatorname{k}=\frac{2.303}{32}\,\,\,log\frac{a}{a-0.75a}\] \[\frac{2.303}{32}\,\,\,log\frac{a}{0.25}\] \[\operatorname{t}\,\,in\,\,50%=\frac{2.303}{k}log\,\frac{100}{50}\] \[=\frac{2.303}{2.303}32\,\frac{log\,2}{log\,4}=16min\].You need to login to perform this action.
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