A) \[{{\operatorname{NaBH}}_{4}}\]
B) \[{{\operatorname{H}}_{2}}-Pd/C\]
C) \[{{\operatorname{LiAlH}}_{4}}\]
D) \[\operatorname{Zn}-Hg/HCl\]
Correct Answer: C
Solution :
It is the reduction of amides by reduction with lithium aluminium hydride\[\left( LiAl{{H}_{4}} \right)\].You need to login to perform this action.
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