A) \[0.77\times 1{{0}^{-5}}m/s\]
B) \[1.77\times 1{{0}^{-5}}m/s\]
C) \[2.08\times 1{{0}^{-5}}m/s\]
D) \[0.55\times 1{{0}^{-5}}m/s\]
Correct Answer: B
Solution :
\[\operatorname{A}=0.3{{m}^{2}},n=2\times 1{{0}^{25}}{{m}^{-2}}\] \[\operatorname{q}=3{{t}^{2}}+5t+2\] \[\frac{dq}{dr}=i=6t+5\] \[\left( t=2s \right)=6\times 2+5=17A\] \[\operatorname{i}=neA{{v}_{\operatorname{d}}}\] \[{{\operatorname{v}}_{d}}=\frac{17}{2\times 1{{0}^{25}}\times 1.6\times 1{{0}^{-19}}\times 0.3}\] \[{{\operatorname{v}}_{d}}=1.77\times {{10}^{-5}}m/s\]You need to login to perform this action.
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