A) 4
B) 2
C) 5
D) 3
Correct Answer: B
Solution :
\[\operatorname{P}\propto {{T}^{3}}(given)\] ?(1) \[{{\operatorname{P}}^{1-\gamma }}{{T}^{\gamma }}=K(given)\] \[\operatorname{P}=K{{T}^{1-\gamma }}\] ?(2) By (1) and (2) \[\frac{-\gamma }{1-\gamma }=3\] \[3-3\gamma =-\gamma \] \[3=2\gamma \] \[\gamma =\frac{3}{2}\]You need to login to perform this action.
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