A) \[2.5m/{{s}^{2}}\]
B) \[2.7m/{{s}^{2}}\]
C) \[2m/{{s}^{2}}\]
D) \[4.5m/{{s}^{2}}\]
Correct Answer: B
Solution :
\[{{\operatorname{a}}_{c}}=\frac{{{v}^{2}}}{r}\] \[{{\operatorname{a}}_{c}}=\frac{30\times 30}{500}=\frac{9}{5}=1.8m/{{s}^{2}}\] \[{{\operatorname{a}}_{\operatorname{t}}}=2m/{{s}^{2}}\] \[{{\operatorname{a}}_{ne\operatorname{t}}}=\sqrt{{{\left( 1.8 \right)}^{2}}+{{\left( 2 \right)}^{2}}}=\sqrt{7.24}\simeq 2.7m/{{s}^{2}}\]You need to login to perform this action.
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