A) \[\vec{i}\,B cos\theta -\vec{j}\,B\,sin\theta \]
B) \[\vec{i}\,B sin\theta +\vec{j}\,B cos\theta \]
C) \[\vec{i}\,B cos\theta +6\vec{j}\,B\,sin\theta \]
D) \[\vec{i}\,B sin\theta +\vec{j}\,B cos\theta \]
Correct Answer: B
Solution :
Two vectors are said to be orthogonal when their dot product is zero. \[\operatorname{A} = \hat{i} A Cos\theta +\hat{j} A Sin\theta \][use option to reduce time] From option \[\left( b \right) \hat{i} B Sin\theta - \hat{j} B Cos\theta .\] Dot product is zero \[\vec{A}. \left( {\vec{b}} \right)=AB Sin\theta Cos\theta - AB Sin\theta Cos\theta =0\]You need to login to perform this action.
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