A) \[\frac{\sqrt{3}{{\mu }_{\operatorname{o}}}}{2\pi }\]
B) \[\frac{{{\mu }_{\operatorname{o}}}}{\pi }\]
C) \[\frac{3{{\mu }_{\operatorname{o}}}}{2\pi }\]
D) \[\frac{{{\mu }_{\operatorname{o}}}}{2\pi }\]
Correct Answer: D
Solution :
At point p \[{{\vec{B}}_{P}}=\frac{m\times 2.5}{2\times 2.5}=\frac{2{{m}_{o}}}{2p}\,\,\otimes \,\,\,into\,the\,\,plane\] \[{{\vec{B}}_{P}}=\frac{\mu \times 5}{2\times 2.5}=\frac{2{{\mu }_{\operatorname{o}}}}{2\pi }\,\,\odot \,\,\,\operatorname{out}\,of\,\,plane\] \[{{\vec{B}}_{net}}={{\vec{B}}_{Q}}-\vec{B}p{{\vec{B}}_{Q}}>{{\vec{B}}_{P}}\] \[=\frac{{{\mu }_{\operatorname{o}}}}{2\pi }\]You need to login to perform this action.
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