A) 1:16
B) 4:1
C) 1: 4
D) 1:1
Correct Answer: C
Solution :
\[{{\operatorname{t}}_{A}}=20\,\,min\] \[{{\operatorname{t}}_{B}}=40\,\,min\] \[{{\operatorname{n}}_{A}}=\frac{T}{{{t}_{A}}}=\frac{80}{20}=4\,\,\,\,\,\,\,\,\,\,\,{{\operatorname{n}}_{\operatorname{B}}}=\frac{80}{40}=2\] \[\therefore {{N}_{A}}={{N}_{B}}(given)\] \[{{N}_{A}}={{N}_{\operatorname{o}}}{{\left( \frac{1}{2} \right)}^{4}}\,{{N}_{B}}=N{{\left( \frac{1}{2} \right)}^{2}}\] \[\frac{{{N}_{A}}}{{{N}_{\operatorname{B}}}}=\frac{1}{4}\]You need to login to perform this action.
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