A) \[\frac{1}{n}\]
B) log k
C) -log k
D) n
Correct Answer: A
Solution :
\[\frac{x}{m}\]Mass of solute adsorbed per gram of adsorbent C = concentrate on of solute \[\frac{x}{m}=K{{C}^{1/n}}\] Taking log both sides \[\log \frac{1}{m}=log\,K+\frac{1}{n}log\,C\Rightarrow slope=\frac{1}{n}\]You need to login to perform this action.
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