A) \[\frac{x+y}{2}\]
B) \[x-y\]
C) \[\sqrt{xy}\]
D) \[x+y\]
Correct Answer: A
Solution :
The given lens is a convex lens. Let the magnification be m, then for real image \[\frac{1}{mx}+\frac{1}{x}=\frac{1}{f}\] ... (i) and for virtual image \[\frac{1}{-my}+\frac{1}{y}=\frac{1}{f}\] ... (ii) From Eq. (i) and Eq. (ii), we get \[f=\frac{x+y}{2}\]You need to login to perform this action.
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