A) Ag 108gm Ni 29.5 gm Cr 17.3 gm
B) Ag 108 gm Ni 59.0 gm Cr 52.0 gm
C) Ag 108.0 gm Ni 108.0 gm Cr 108.0 gm
D) Ag 108 gm Ni 117.5 gm Cr 166.0 gm
Correct Answer: A
Solution :
Wt. of Ag deposited = Eq. wt of Ag = 108 gn Wt. of Ni deposited = Eq. wt of Ni == 29.5 gm. Wt. of Cr deposited = Eq. wt of Cr = 17.3 gm.You need to login to perform this action.
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