A) Acetylide
B) Methanide
C) Allylide
D) Propenide
Correct Answer: B
Solution :
\[\begin{align} & A{{1}_{4}}{{C}_{3}}+12H-OH\xrightarrow{{}}4A1{{(OH)}_{3}}+3C{{H}_{4}} \\ & \,\,\,{{\,}^{3{{C}^{-4}}}} \\ \end{align}\]You need to login to perform this action.
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