A) 1.81
B) 1.71
C) 1.91
D) 1.76
Correct Answer: C
Solution :
\[2.303\,\log \,\frac{{{K}_{2}}}{{{K}_{1}}}=\frac{{{E}_{A}}}{R}\,\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right];\] \[T=280\,K;\,T=290K;\frac{{{K}_{2}}}{{{K}_{1}}}=2\] Find \[{{E}_{a}}\] and then again use: \[2.303\,\,\log \,\frac{K{{'}_{2}}}{K{{'}_{1}}}=\frac{{{E}_{A}}}{R}\left[ \frac{T{{'}_{2}}-T}{{{T}_{1}}'T{{'}_{2}}} \right]\] If \[{{T}_{1}}'=290\,K;\,{{T}_{2}}'=300\,K;\]You need to login to perform this action.
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