A) \[N{{a}_{2}}O\]
B) \[N{{a}_{2}}{{O}_{2}}\]
C) \[L{{i}_{2}}{{O}_{2}}\]
D) \[K{{O}_{2}}\]
Correct Answer: D
Solution :
\[K{{O}_{2}}+HOH\to \text{ }KOH+{{H}_{2}}{{O}_{2}}+{{O}_{2}}\] \[N{{a}_{2}}{{O}_{2}}+2HOH\to 2NaOH+{{H}_{2}}{{O}_{2}}\] \[N{{a}_{2}}\text{O}+HOH\to NaOH\]
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