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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    The rate constant of a second order reaction is \[{{10}^{-2}}\] \[mo{{l}^{-1}}\] litre \[{{\sec }^{-1}}\]. The rate constant when expressed in \[c{{m}^{3}}\]\[molecul{{e}^{-1}}\] \[{{\min }^{-1}}\] is :

    A) \[9.96\times {{10}^{-22}}~~\]            

    B) \[9.96\times {{10}^{-23~}}~\]

    C) \[9.96\times {{10}^{-21~}}\]               

    D) \[1.004\times {{10}^{-24}}\]

    Correct Answer: A

    Solution :

    \[K\text{ }={{10}^{-2}}mo{{l}^{-1}}\text{ }litre\text{ }se{{c}^{-1}}\] \[=\frac{{{10}^{-2}}\times 1000\times 60}{6.02\times {{10}^{23}}}\,\,cc\,molecul{{e}^{-1}}\text{ mi}{{\text{n}}^{-1}}\] \[=9.9618\times {{10}^{-22}}\,\,cc\,molecul{{e}^{-1}}\text{ mi}{{\text{n}}^{-1}}\]


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