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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    The decomposition of \[{{N}_{2}}{{O}_{4}}\]to \[N{{O}_{2}}\] is carried out at 280 K in chloroform. When equilibrium has been established, 0.2 mol of \[{{N}_{2}}{{O}_{4}}\] and \[2\times {{10}^{-3}}\] mol of \[N{{O}_{2}}\] are present in 2 litre solution. The equilibrium constant for reaction \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}\] is:

    A) \[1\times {{10}^{-2}}\]            

    B) \[2\times {{10}^{-3}}\]

    C) \[1\times {{10}^{-5}}~\]                     

    D) \[2\times {{10}^{-5}}\]

    Correct Answer: C

    Solution :

    \[K=\frac{{{[N{{O}_{2}}]}^{2}}}{[{{N}_{2}}{{O}_{4}}]}=\frac{{{\left[ 2\times \frac{{{10}^{-3}}}{2} \right]}^{2}}}{\left[ \frac{2}{2} \right]}=\frac{{{10}^{-6}}}{{{10}^{-1}}}={{10}^{-6}}\]


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