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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    For the reaction: \[2N{{H}_{3}}\to {{N}_{2}}+3{{H}_{2}}\]we have: \[-\frac{d[N{{H}_{3}}]}{dt}={{k}_{1}}[N{{H}_{3}}],\frac{d[{{N}_{2}}]}{dt}={{k}_{2}}[N{{H}_{3}}]\]and \[\frac{d[{{H}_{2}}]}{dt}={{k}_{3}}[N{{H}_{3}}]{{k}_{1}},{{k}_{2}}\]and \[{{k}_{3}}\] are related as:

    A) \[{{k}_{1}}={{k}_{2}}={{k}_{3}}\]               

    B) \[3{{k}_{1}}=6{{k}_{2}}=2{{k}_{3}}\]

    C) \[2{{k}_{1}}=3{{k}_{2}}=6{{k}_{3}}~~\]    

    D) \[6{{k}_{1}}=3{{k}_{2}}=2{{k}_{3}}\]

    Correct Answer: B

    Solution :

    \[-\frac{1}{2}\frac{d[N{{H}_{3}}]}{dt}=\frac{d[{{N}_{2}}]}{dt}=\frac{1}{3}\frac{d[{{H}_{2}}]}{dt}\] \[\frac{1}{2}{{k}_{1}}(N{{H}_{3}})={{k}_{2}}(N{{H}_{3}})=\frac{1}{3}{{k}_{3}}(N{{H}_{3}})\] or \[\frac{{{k}_{1}}}{2}={{k}_{2}}=\frac{{{k}_{3}}}{3}\,or\,3\,{{k}_{1}}=6{{k}_{2}}=2{{k}_{3}}\]


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