A) \[\operatorname{v}=\sqrt{2gR}\]
B) \[\operatorname{v}=\sqrt{gR}\]
C) \[\operatorname{v}=2\sqrt{gR}\]
D) \[\operatorname{v}=\sqrt{\frac{gR}{2}}\]
Correct Answer: B
Solution :
Weight of disc = mg, this provides the necessary centripetal force \[\operatorname{mg}=\frac{m{{v}^{2}}}{R}\] \[\operatorname{v}=\sqrt{gR}\]You need to login to perform this action.
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