A)
B)
C)
D)
Correct Answer: C
Solution :
Since \[{{\operatorname{CH}}_{3}}O\] is a strong nucleophile as well as strong base, it can either bring about substitution or elimination. Now \[{{\operatorname{CH}}_{3}}\]group at P-carbon causes \[{{\operatorname{S}}_{N}}2\]therefore elimination occurs preferentially to form 2 methyl propene.You need to login to perform this action.
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