A) 2v
B) 4v
C) 8v
D) 16v
Correct Answer: B
Solution :
Terminal velocity \[\left( {{V}_{T}} \right)=\frac{2}{9}\frac{\left[ \rho -\sigma \right]{{r}^{2}}}{\eta }\] \[\operatorname{Mass} of sphere m = \frac{4}{3} \pi {{r}^{3}}\rho \] \[\operatorname{m}\propto {{r}^{3}}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right)}^{{}^{1}/{}_{3}}}={{\left( \frac{m}{8m} \right)}^{{}^{1}/{}_{3}}}\] Use this result to calculate ratio of terinal velocity \[\frac{{{V}_{{{T}_{1}}}}}{{{V}_{{{T}_{2}}}}}=\frac{{{r}^{2}}_{1}}{{{r}^{2}}_{2}}=\frac{1}{4}\] \[{{\operatorname{V}}_{{{T}_{2}}}}=4V\]You need to login to perform this action.
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