A) 0.1
B) 0.2
C) 0.3
D) 0.4
Correct Answer: D
Solution :
\[\operatorname{Volume} flow rate = Velocity \times Cross\]sectional area \[200c{{m}^{3}}/s=V\times 0.5{{m}^{2}}\] \[200\times 1{{0}^{-6}}{{m}^{3}} /s=V\times 0.5{{m}^{2}}\] \[\operatorname{V}=400\times 1{{0}^{-6}}/sec\] \[\operatorname{V}=0.4mm/sec \left[ \therefore 1m=1{{0}^{3}}mm \right]\]You need to login to perform this action.
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