A) 0.1V
B) 0.5V
C) 1V
D) 5V
Correct Answer: D
Solution :
\[\operatorname{Induced} emf ==\frac{d\phi }{dt}\] \[\phi =BA\,\,cos\theta \] \[\phi =BA\,\,cos0{}^\circ =BA\] \[\operatorname{emf}=\frac{d\left( BA \right)}{dt}=\frac{dB}{dt}A\] \[\operatorname{emf} = \frac{nA.dB}{dt}~~~~~\left[ for 'n' = 500 turns \right]\] \[\operatorname{emf}500\times \frac{10\times 10}{100\times 100}\times 1=5V\]You need to login to perform this action.
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