A) \[\frac{l}{9}\]
B) \[\frac{\operatorname{l}}{4}\]
C) \[\frac{\operatorname{l}}{16}\]
D) \[\frac{\operatorname{l}}{3}\]
Correct Answer: C
Solution :
Acceleration due to gravity \[\operatorname{g}=\frac{GM}{{{R}_{e}}^{2}}\] ?(1) \[\operatorname{g}''=\frac{GM}{{{\left( {{\operatorname{R}}_{e}}+H \right)}^{2}}}\] \[\operatorname{g}''=\frac{1}{16}\frac{GM}{{{\operatorname{R}}_{e}}^{2}}\] ?.(2) By (1) and (2) \[\frac{g}{g''}=\frac{1}{16}\]You need to login to perform this action.
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