A) 4s
B) 2s
C) 8s
D) 10s
Correct Answer: B
Solution :
The angle by which voltage leads Current is given by \[\tan \phi =\frac{{{X}_{L}}}{R}\] \[\operatorname{R}=1\Omega ,\,\,f=50Hz,\,\,{{X}_{L}}=\omega L,\,L=1{{0}^{-2}}H\] \[=\tan \phi =\frac{\omega \operatorname{L}}{\operatorname{R}}=\frac{2\pi fL}{R}\] \[=\tan \phi =\frac{2\pi \times 50\times {{10}^{-2}}}{1}=\pi \] \[=\phi ={{\tan }^{-1}}\left( \pi \right)\]You need to login to perform this action.
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