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NEET Sample Paper NEET Sample Test Paper-45

  • question_answer
    The moment of inertia of a disc about an axis passing through its centre and normal to its plane is I. The disc is now folded along a diameter such that the two halves are mutually perpendicular. Its moment of inertia about this diameter will now be-

    A) I                                  

    B) \[I/\sqrt{2}\]

    C) \[I/2\]               

    D) \[I/4\]

    Correct Answer: C

    Solution :

    \[I=\frac{1}{2}\,\,m{{R}^{2}}\]  For a diameter; \[I'=\frac{1}{2}\]


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