question_answer

A converging lens forms an image of an object on a screen. The image is real & has twice the size of the object. If the positions of the screen & the object are interchanged, leaving the lens in its original position, what is the new image size on the screen.

A) Twice the object size

B) Same as the object size

C) Half the object size

D) Can?t say as it depends on the focal length of the lens

Correct Answer: C

Solution :

  \[{{m}_{1}}{{m}_{2}}=1\] \[{{m}_{2}}\,\,=\,\,\frac{1}{{{m}_{1}}}\] \[{{m}_{2}}\,\,=\,\,\frac{1}{2}\]