A) time
B) mass
C) volume
D) velocity
Correct Answer: A
Solution :
\[\left[ \sqrt{\frac{2h}{g}} \right]\,\,=\,\,\sqrt{\frac{{{M}^{0}}{{L}^{1}}{{T}^{0}}}{{{M}^{0}}{{L}^{1}}{{T}^{-2}}}}\,\,=\,\,\sqrt{{{M}^{0}}{{L}^{1}}{{T}^{2}}}\,\,\left[ {{T}^{1}} \right]\,\,=\,\,Time\]You need to login to perform this action.
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