A) 2 mg R
B) \[\frac{mgR}{2}\]
C) 3 mg R
D) \[\frac{2mgR}{3}\]
Correct Answer: D
Solution :
\[W=\Delta \left( PE \right)=GMm\,\,\left[ \frac{1}{R}-\frac{1}{3R} \right]\] \[=\,\,\frac{2GMm}{R}\,\,=\,\,\frac{2}{3}\,gm\,\,R\]You need to login to perform this action.
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