A) 500 mA
B) 510 mA
C) 610 mA
D) 490 mA
Correct Answer: B
Solution :
\[S=G\frac{{{I}_{g}}}{I-{{I}_{g}}}\] \[1=50\times \frac{10}{I-10}\] \[I-10=500\] \[I=510\,mA\]You need to login to perform this action.
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