A) 1.0
B) 3.0
C) 4.0
D) 6.0
Correct Answer: A
Solution :
Total moles at equilibrium \[=3+3+3=9\] moles Partial pressure of \[PC{{l}_{3}}\]} or \[C{{l}_{2}}\] or \[PC{{l}_{5}}=\frac{3}{9}\times 3=1\] \[\therefore \,\,\,\,\,\,\,\,\,\,{{K}_{p}}\,=\,\,\frac{{{P}_{PC{{l}_{3}}}}.\,{{P}_{C{{l}_{2}}}}}{{{P}_{PC{{l}_{5}}}}}\,\,=\,\,\frac{1\times 1}{1}\,\,=\,\,1.0\]You need to login to perform this action.
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