A) \[40%\]
B) \[60%\]
C) \[80%\]
D) \[100%\]
Correct Answer: A
Solution :
Effeciency of respiration of one molecule of Glucose 1 mol. glucose = 686 Kcal energy conserved It?s complete oxidation produce = 36 ATP \[1\,\,ATP=7.6\text{ }K.Cal.\] \[\frac{36\times 7.6}{686}\,\,\times \,\,100\,\,=\,\,39.88%\]You need to login to perform this action.
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