A) 1:1
B) \[\sqrt{2}:1\]
C) \[1:\text{ }\sqrt{2}\]
D) 2:1
Correct Answer: A
Solution :
\[\frac{{{\lambda }_{\alpha }}}{{{\lambda }_{d}}}=\frac{\frac{h}{4mv}}{\frac{h}{2m2v}}=\frac{1}{1}\]
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