A) \[120{}^\circ C\]
B) \[100{}^\circ C\]
C) \[140{}^\circ C\]
D) \[\text{ }80{}^\circ C\]
Correct Answer: C
Solution :
\[{{H}_{1}}\,\,=\,\,2{{H}_{2}}\] \[\frac{KA}{\ell }\,\,(200-T)\,\,=\,\,2\frac{KA}{\ell }\,\left( T-T' \right)\] \[200=2T-T'\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,......(1)\] \[2{{H}_{2}}={{H}_{3}}\] \[2\frac{KA}{\ell }\,\,(T-T')\,\,=\,\,\left( T'-20 \right)\,\frac{KA}{\ell }\] \[2T'-T=20\] ?? (2) By solving (1) & (2) \[T\,\,=\,\,140\]You need to login to perform this action.
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