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NEET Sample Paper NEET Sample Test Paper-46

  • question_answer
    A silicon specimen is made into a p-type semiconductor by doping on an average one indium atom per \[5\times {{10}^{7}}\] silicon atoms. If the number density of atoms in the silicon specimen is \[5\times {{10}^{26}}\] atoms/metre3 then the number of acceptor atoms in silicon per cubic centimeter will be -

    A) \[2.5\times {{10}^{30}}\]

    B) \[1.0\times {{10}^{13}}\]

    C) \[1.0\times {{10}^{15}}\]

    D) \[2.5\times {{10}^{36}}\]

    Correct Answer: C

    Solution :

    \[\because \,\,\,5\text{ }\times \text{ }{{10}^{7}}have\,\,=\,\,1\] impurity \[\therefore \,\,\,\,\,\,\,\,\,\,l\,\,\,\_\_\_\_\_\_\_\_=\frac{1}{5\,\,\times \,\,{{10}^{7}}}\] \[\therefore \,\,\,\,\,\,\,\,\,5\,\,\times \,\,{{10}^{26}}\,\,\,\_\_\_\_\_\_\_\_=\frac{5\times {{10}^{26}}}{5\,\,\times \,\,{{10}^{7}}}\,\,=\,\,{{10}^{19}}\,\,\frac{atom}{{{m}^{3}}}\]\[=\,\,\frac{{{10}^{19}}}{{{10}^{6}}}\,\frac{atom}{c{{m}^{3}}}\,\,=\,\,{{10}^{13}}\,\frac{atom}{c{{m}^{3}}}\]


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