A) \[\frac{1}{e}\]
B) \[\frac{e}{2}\]
C) \[\frac{1}{{{e}^{4}}}\]
D) \[\frac{1}{{{e}^{2}}}\]
Correct Answer: D
Solution :
\[\frac{{{N}_{1}}}{{{N}_{0}}}=\,\,\frac{{{N}_{0}}{{e}^{-15x\times t}}}{{{N}_{0}}{{e}^{-3x\times t}}}\,\,=\,\,\frac{1}{{{e}^{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec