A) 2
B) 4
C) 6
D) 8
Correct Answer: B
Solution :
Here, whistle B and listener (both) are moving with same speed. Hence, there will be no change in the pitch of whistle B to the listener. Frequency of the note from A will be: \[n'=n\left( \frac{v-{{v}_{0}}}{v} \right)\,\,=\,\,600\,\left( \frac{330-30}{330} \right)\,\,=\,\,600\,\,Hz\] \[\therefore \,\,\,Beat\,\,frequency=\text{ }600-596=4\text{ }Hz.\]You need to login to perform this action.
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