A) \[3\pi T{{r}^{2}}\,joule\]
B) \[6\pi T{{r}^{2}}\,joule\]
C) \[12\pi T{{r}^{2}}\,joule\]
D) \[24\pi T{{r}^{2}}\,joule\]
Correct Answer: D
Solution :
\[\Delta U\,\,=\,\,2\,[4\pi {{(2r)}^{2}}-4{{\pi }^{2}}]\] \[=\,\,\,24\pi {{r}^{2}}T\]You need to login to perform this action.
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