A) \[\mu >\frac{\sqrt{3}}{2}\]
B) \[\mu <\frac{3\sqrt{3}}{4}\]
C) \[\mu >\sqrt{3}\]
D) \[\mu <\frac{\sqrt{3}}{2}\]
Correct Answer: B
Solution :
\[60{}^\circ >C\] \[sin\text{ }60{}^\circ >sin\text{ }C\] \[\frac{\sqrt{3}}{2}>\frac{{{\mu }_{r}}}{{{\mu }_{D}}}\] \[\frac{\sqrt{3}}{2}>\frac{\mu }{3/2}\,\,so\,\,\mu \,\,<\,\,\frac{3\sqrt{3}}{4}\]You need to login to perform this action.
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