A) zero
B) \[{{q}^{2}}/C\]
C) \[{{q}^{2}}/2C\]
D) \[{{q}^{2}}/4C\]
Correct Answer: C
Solution :
\[{{C}_{1}}=C\,\,=\,\frac{{{\in }_{0}}\,A}{d}\] \[{{C}_{2}}=\frac{C}{2}\,\,=\,\,\frac{{{\in }_{0}}\,A}{2d}\] \[W\,\,=\,\,\left( \frac{{{Q}^{2}}}{2{{C}_{2}}}-\frac{{{Q}^{2}}}{2{{C}_{1}}} \right)\,\,=\,\,\frac{{{Q}^{2}}}{2C}\,\]You need to login to perform this action.
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