A) 2.7 Kcal
B) -2.7 Kcal
C) 9.3 Kcal
D) -9.3 Kcal
Correct Answer: A
Solution :
\[\underset{(l)}{\mathop{{{X}_{2}}{{O}_{4}}}}\,~\,\,\to ~\,\,\underset{(g)}{\mathop{2X{{O}_{2}}}}\,\] \[\Delta H=\Delta E+\Delta ngRT\] \[=2.1+2\times \left( \frac{2}{1000} \right)\times 300\] \[=2.1+1.2\] \[=\text{ }3.3\text{ }Kcal\] \[\Delta G=\Delta H-T\Delta S\] \[=3.3\,\,-\,\,300\,\times \,\,\frac{20}{1000}\] \[=2.7\text{ }Kcal.\]You need to login to perform this action.
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